WebThe unit for the concentration of hydrogen ions is moles per liter. To determine pH, you can use this pH to H⁺ formula: pH = -log ( [H⁺]) Step by Step Solution to find pH of 0.033 M : … WebCalculate the pH of the solution after the addition of each of the given amounts of 0.0542 M HNO3 to a 60.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. What is the pH of the solution after the addition of 78.2 mL HNO3? What is the pH of the solution after the addition of a volume
Question: Determine the pH of a 0.033 M HNO3 solution.
WebIn this exercise, we will calculate the p H \ce{pH} pH and p O H \ce{pOH} pOH from the molar concentrations of some strong acids and bases. For strong acids and bases, the … WebMay 14, 2024 · The concentration of [ OH- ] can then be used to calculate the pOH of the solution. pH = 14 - pOH = 14 - 1.48 = 12.52. Therefore, the pH of a 0.033 M KOH solution would be 12.52. mark it on brilliant list . Advertisement Advertisement fardeenferozkhan fardeenferozkhan Answer: easybeast download
Answered: Determine the pH change when 0.072 mol… bartleby
WebApr 3, 2024 · pH + pOH = 14. Since. pOH = − log([OH−]) you can say that the pH of a solution is given by. pH = 14 +log([OH−]) In your case, this will be equal to. pH = 14 +log(√0.49⋅ Kb) Now all you have to do is to use the value of the base dissociation constant given to you--or you can simply do a quick search for the base dissociation constant ... WebTo calculate the pH of the solution containing ammonia and NH4Cl, we will use the Handerson Hasselbach equation.According to this equation,pOH = pKb + log [Salt]/[Base]where, pKb is to be calculated from Kb.Kb for NH3 = 1.77×10-5pKb = -log Kb = -log (1.77×10-5) = 4.75[Salt] = [NH4Cl] = 0.033 M[Base] = [NH3] = 0.033 MWhen we put … WebMay 14, 2024 · Hi Jose! I would love to help you with this problem. Since KOH is a strong base, the solution completely ionizes into K + and OH - when in water.. The reaction KOH --> K + + OH-takes place.. Since KOH … easy bears shirts